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Mitered Elbow Allowable Pressure Calculator (ASME B31.3 ¶304.2.3)

Outputs Pm1 from Eq. (4a), Pm2 from Eq. (4b), and the governing allowable pressure of a mitered elbow as the lesser of the two, naming the controlling equation, per ASME B31.3 ¶304.2.3. Single miters steeper than 22.5° take the 1.25-coefficient form of ¶304.2.3(b).

Mitered elbows concentrate stress at the miter joints, so B31.3 limits their internal pressure below that of straight pipe. This calculator evaluates Eq. (4a) and (4b) for closely spaced multi-miter bends (θ ≤ 22.5°) — the governing allowable is the lesser — and the 1.25-coefficient single-miter form for larger cut angles.

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Method

Pm1 = (S·E·Tc/r2) · Tc / ( Tc + 0.643·tan θ·√(r2·Tc) )  (Eq. 4a)

Pm2 = (S·E·Tc/r2) · (R1 − r2) / (R1 − r2/2)  (Eq. 4b)

Single miter with θ > 22.5° replaces the 0.643 coefficient with 1.25 (Eq. 4c). Tc is the wall available after tolerances and allowances, r2 the mean pipe radius, R1 the effective bend radius, θ the miter half-angle.

Inputs
S, EAllowable stress and quality factor (user-supplied)psi, —
TcWall available for pressure (net of tolerances/allowances)in
r2Mean pipe radius (D − t)/2in
R1Effective miter bend radiusin
θMiter half-angledeg
mitersNumber of miter cuts
Outputs
Pm1Eq. (4a) allowablepsi
Pm2Eq. (4b) allowable (multi-miter)psi
PGoverning allowable pressure + equationpsi

Limitations — what this calculator is not

Worked example — fixture-verified

3-cut miter, half-angle 15°, S = 20,000 psi, E = 1.0, available wall Tc = 0.25 in, mean radius r2 = 4.1515 in, effective bend radius R1 = 12 in.

Given
Allowable stress S20,000psi
Quality factor E1.0
Available wall Tc0.25in
Mean radius r24.1515in
Bend radius R112in
Half-angle θ15deg
Miter cuts3

Step by step

  1. Base term: S·E·Tc/r2 = 20,000·0.25/4.1515 = 1,204.4 psi.
  2. Eq. (4a): 0.643·tan15°·√(4.1515·0.25) = 0.643·0.26795·1.01876 = 0.17551; Pm1 = 1,204.4 · 0.25/(0.25+0.17551) = 1,204.4·0.58752 = 707.6 psi.
  3. Eq. (4b): Pm2 = 1,204.4 · (12−4.1515)/(12−2.0758) = 1,204.4·0.79084 = 952.5 psi.
  4. Governing: min(707.6, 952.5) = 707.6 psi — Eq. (4a) governs.
Result COMPUTED
Pm1 (Eq. 4a)707.6psi
Pm2 (Eq. 4b)952.5psi
Governing allowable707.6psi

The same straight pipe rates ~1,150 psi — the miter geometry costs roughly 40% of the pressure capacity here, which is why miters live in low-pressure large-bore service.

Why you can trust these numbers: this exact case is fixture miter-allowable-pressure.json — case “3-miter, theta=15deg, Tc=0.25, r2=4.1515, R1=12, S=20000” (tolerance 0.001) — in the calc-core release gate. It re-runs on every commit; a red fixture blocks deployment. See the validation methodology.

Sources & citations

Per the source & citation policy, allowable-stress and factor table values are user-supplied — this page and the app cite paragraph numbers and never reproduce ASME table data.

FAQ

Why do miter bends rate lower than smooth elbows?

The angular discontinuity at each miter joint produces local bending of the pipe wall under pressure. Eq. (4a) captures that knockdown as a function of the cut angle and wall; the sharper the cut, the lower the allowable.

What counts as a 'widely spaced' miter?

When the distance between cuts exceeds the Code's closely-spaced criterion, each joint behaves as an independent single miter — rate it with the single-miter (1.25 coefficient) form. This card handles both by the miter count and angle you enter.

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